#### Question:

An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y when it contains x cups of water?

Posted By Admin @ September 03, 2022

An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y when it contains x cups of water?

**Answer: **jugs weight ⇒ y = 0.75 + 0.5 x

**Step-by-step explanation:**

Hi, to solve this problem we have to analize the information given.

So:

Empty jug weight = 0.75 lbs

jug with 3 cups of water weight =2.25

The next step is to subtract the weight of the empty jug to the weight of the jug with 3 cups.

2.25 -0.75= 1.5 lbs

We have calculated the weight of 3 cups of water. To calculate the weight of one cup we simply divide the result by 3.

1.5 /3 = 0.5 lbs ( 1 cup)

Finally, we have the information needed for the equation. It wiil be the weight of the empty jug plus the weight of one cup of water multiplied by x.

jugs weight **(y) = 0.75 + 0.5 x **

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