Question:
An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y when it contains x cups of water?
Posted By Admin @ September 03, 2022
An empty 5 gallon water jug weighs 0.75 lbs. With 3 cups of water inside, the jug weighs 2.25 lbs. What equation models the jug's weight y when it contains x cups of water?
Answer: jugs weight ⇒ y = 0.75 + 0.5 x
Step-by-step explanation:
Hi, to solve this problem we have to analize the information given.
So:
Empty jug weight = 0.75 lbs
jug with 3 cups of water weight =2.25
The next step is to subtract the weight of the empty jug to the weight of the jug with 3 cups.
2.25 -0.75= 1.5 lbs
We have calculated the weight of 3 cups of water. To calculate the weight of one cup we simply divide the result by 3.
1.5 /3 = 0.5 lbs ( 1 cup)
Finally, we have the information needed for the equation. It wiil be the weight of the empty jug plus the weight of one cup of water multiplied by x.
jugs weight (y) = 0.75 + 0.5 x
Feel free to ask for more if it´s necessary or if you did not understand something