This question is incomplete, the complete question is;

Car B is rounding the curve with a constant speed of 54 km/h, and car A is approaching car B in the intersection with a constant speed of 72 km/h. The x-y axes are attached to car B. The distance separating the two cars at the instant depicted is 40 m. Determine: the angular velocity of Bxy rotating frame (ω).

**Answer:**

the angular velocity of Bxy rotating frame (ω) is **0.15 rad/s**

**Explanation:**

Given the data in the question and image below and as illustrated in the second image;

distance S = 40 m

V = 54 km/hr

V = 72 km/hr

α = 100 m

now, angular velocity of Bxy will be;

ω = V / α

so, we substitute

ω = ( 54 × 1000/3600) / 100

ω = 15 / 100

ω = **0.15 rad/s**

Therefore, the angular velocity of Bxy rotating frame (ω) is **0.15 rad/s**